7w^2-8w+1=0

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Solution for 7w^2-8w+1=0 equation:



7w^2-8w+1=0
a = 7; b = -8; c = +1;
Δ = b2-4ac
Δ = -82-4·7·1
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-6}{2*7}=\frac{2}{14} =1/7 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+6}{2*7}=\frac{14}{14} =1 $

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